Asked by: Weijie Hilario
asked in category: technology and computing Last Updated: 24th November, 2020

How do you pass a pointer to a function in C++?

In this example, we are passing a pointer to a function. When we pass a pointer as an argument instead of a variable then the address of the variable is passed instead of the value. So any change made by the function using the pointer is permanently made at the address of passed variable.

Read rest of the answer. Consequently, how do you pass a pointer to a function in C++?

To pass the value by pointer, argument pointers are passed to the functions just like any other value. So accordingly you need to declare the function parameters as pointer types as in the following function swap(), which exchanges the values of the two integer variables pointed to by its arguments.

Furthermore, how do you pass a pointer to an array to a function? Passing array to function using call by reference When we pass the address of an array while calling a function then this is called function call by reference. When we pass an address as an argument, the function declaration should have a pointer as a parameter to receive the passed address.

Also question is, what is pointer to a function in C++?

Function Pointers in C and C++ By Alex Allain. A function pointer is a variable that stores the address of a function that can later be called through that function pointer. This is useful because functions encapsulate behavior.

How do you pass a pointer to a function?

When we pass a pointer as an argument instead of a variable then the address of the variable is passed instead of the value. So any change made by the function using the pointer is permanently made at the address of passed variable. This technique is known as call by reference in C.